Speeds of two identical cars are u are 4u at a specific instant. The ratio of the respective distances in which the two cars are stopped in the same time
Text Solution
Verified by ExpertsThe correct answer is:
B
For first car,
u 1 = u, v 1 = 0, t 1 = t
∴ v 1 = u 1 + a 1 t
0 = u – a 1 t
∴ u = a 1 t.......(i)
Now, v 1 2 = u 1 2 + 2a 1 s 1
0 = u 2 – 2 a 1 s 1
u 2 = 2a 1 s 1
⇒ u 2 = 2 × 
× s 1
∴ s 1 = 
..........(ii)
For second car,
u 1 = 4u, v 2 = 0
∴ v 2 = u 2 + at
0 = 4u – a 2 t
a 2 = 
.........(iii)
Now, v 2 2 = u 2 2 + 2a 2 s 2
0 = u 2 2 – 2a 2 s 2
(4u) 2 = 2 × 
× s 2
∴ s 2 = 
.......(iv)
∴ 
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